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Advanced Compression Spring Design

價格:免費

更新日期:2018-10-10

檔案大小:2.0M

目前版本:1.0

版本需求:Android 2.2 以上版本

官方網站:http://hyc-tech.com/spring/

Email:info@hyc-tech.com

聯絡地址:48408 Red Run Drive Red Run Drive Canton, MI 48187

Advanced Compression Spring Design(圖1)-速報App

When you run this program for the first time on your Android device, the program creates 21 predefined identical design cases. You need to modify the parameters of these cases for your own design. Then you can save your new design cases for future use or reference.

There are 5 pages in this program. Each page has a page id shown on the top line of the screen. Theses pages contain the following command buttons:

(Main)

Spring Design

Instruction

Spring Materials, Wire Specs

Exit to AndroidOS

(Selection)

Back to Main

Go Designing

(Designing)

Back to Main

Design It!

Save This Design

(Info)

Back to Main

(Material)

Back to Main

UNITS USED:

Force Unit: N

Length Unit: mm

Stress Unit: Mpa

SPRING MATERIALS:

Fourteen common spring materials are included in this program.

1: A228

2: A227a

3: A227b

4: A679HT

5: A229OT1

6: A229OT2

7: A230

8: A231_A232

9: A878

10: A401

11: A313a

12: A313b

Advanced Compression Spring Design(圖2)-速報App

13: A313c

14: A313d

SPRING RATE OF AXIALLY LOADED SPRINGS

The mechanics of compression or extension spring can be interpreted from the formulation of forces and stress of just one coil. For a ring coil, two opposite forces of equal magnitude are applied at the each ends. After the force is applied these two ends move a relative distance e. The load is acting parallel to the coil axial. This load is resisted by the spring through a twisting torsion developed in the coil wire. The coil wire total twisting is:

Bar twist angle of one loop = Torque * (One loop length)/(G shear modulus * J torsional inertia)

H = T * L / (G J) = (F * R) * L / (GJ)

Where T = Torque = F * R = Force * Radius = F * D/2

F = Coil Spring Axial Force

L = Length of One Loop = Pi * D

D = Coil Diameter

J = Pi * d ^ 4 /32

d = wire diameter

Pi = 3.14159

Therefore

H = (F * D/2)* (Pi * D )/ (G * Pi * d ^ 4 /32)

= F * D^2 * Pi / ( G * Pi * d^4 / 16)

= 16 * F * D^2/(G * d^4)

One loop’s elongation along axial direction = e = R * H = D * H /2 = 8 * F * D^3/(G * d^4)

Spring Rate for one loop = k = F / e = (G * d^4)/(8 * D^3)

For n loops, total elongation = E = e * n

So the spring rate for the whole spring is F / E = (G * d^4)/(8 * n * D^3)

SPRING END CONDITION

Compression spring can have many end conditions to achieve stability

Closed ends: spring wire end contacts the next loop.

Closed and ground ends: spring wire end ground and contacts the next loop.

Plain ends: spring wire end does not contact next loop

Plain ends ground: spring wire end ground that does not contact next loop

STRESSES AND ALLOWABLE STRESSES

The torsion stress in the compression spring is:

T = (8 F D K )/(Pi * d ^3)

Advanced Compression Spring Design(圖3)-速報App

Where K = ( c + 0.2 )/ ( c -1)

C= D/d = spring index

Advanced Compression Spring Design(圖4)-速報App